Math, asked by manya2863, 17 days ago

if x=9-4√5 then find (x-1/x)^2 and x^2-1/x^2 ​

Answers

Answered by s49402841
0

Step-by-step explanation:

If x=9-4√5, then what is x+1/x?

x=9–45–√

1x=19–45√

x+1x=9–45–√+19–45√

x+1x=(9–45√)2+19–45√

x+1x=81+16(5)−2(9)(45√)+19–45√

x+1x=81+80−725√+19–45√

x+1x=162−725√9–45√

x+1x=18(9−45√)9–45√

x+1x=18

If x=9-4√5, what is x-1/x?

If x=9-4√5, then what is x^2+1/x^2?

What is x+1/x if x value is 5-2√3?

If x=9+4root5, what is the value of (x) ^4+(1/x) ^4?

If x=9-4√5, what is (7)2+1/(x)2?

x=9−4√5

(9−x)=4√5

squaring both sides we get

81+x2+−18x=80

x2+1=18x

x+1x=18

x = 9 - 4 √5.

Since (a+b)(a - b) = a^2 - b^2

(9 - 4 √5)(9 + 4 √5) = 81 - 80 = 1

=>9 - 4 √5 = 1/(9 +4 √5) which is ‘x’

Therefore we can write 1/x = 9 + 4 √5

=> x + 1/x = (9 - 4 √5) + (9 + 4 √5) = 9 + 9 = 18.

x = 9 - 4√5

1/x = 1/(9 - 4√5)

Now rationalise it

= [1/(9 - 4√5)] × [(9 + 4√5)/(9 + 4√5)]

= (9+4√5)/[(9)^2 - (4√5)^2]

= (9+4√5)/(81 - 80)

= 9+4√5

.°. x + 1/x = (9 - 4√5) + (9 + 4√5)

= 18.

Is x+y−−−−√=x−−√+y√ ?

What is the value of [1/ (2+√3-2√2)] + [3/ (2+√3+2√2)]?

How do I rationalise 2−1√√2+1√√ ?

If x=9-4√5, what is x2+1/x2?

If 140√x +315=1015, then x is equal to what?

Given x = 9 - 4√5

So 1/x = 1/(9–4√5)

= (9+4√5)/{(9+4√5)(9–4√5)}

= (9+4√5)/(81–80)

= 9+4√5

Hence x+ 1/x = 9-4√5 + 9+4√5 = 18

x = 9–4sqrt5

x + 1/x = ?

Substitute for x:

9–4sqrt5 + 1/(9–4sqrt5)

Multiply both terms by the denominator, which is (9–4sqrt5). In the fraction, the two cancel each other out and you’re left with 1. But for the other term, you end up with 81–16*5, which is 81–80.

That leaves you with just 1. Add 1 to that and you get 2.

X=9–4√5

X=9–4×2.236 (value of √5 = 2.2360)

X=9 - 8.944

X=0.056

X+1/X = 1+0.056/0.056

X+1/X=1.056/0.056=18.857

So the answer is 18.857

x+1x=(9−45–√)+19−45–√=(9−45–√)+9+45–√1=18

x= 9--4 (5)^1/2

Rationalise

x = 9-4(5)^1/2 ×9+4(5)^1/2 /9+4(5)^1/2

=( (9)^2 --16 ×5 ) /9+4(5)^1/2 =1/9+ 4(5)^1/2

x+1/x = 9--4(5)^1/2 + 9+ 4(5)^1/2 = 18

The required answer is 18

1/x=1/(9–4\/5)

x+1/x=(9–4\/5)+1/(9–4\/5)

=10–4\/5/9–4\/5

Rationalizing the denominator,we get,

(10–4\/5)(9+4\/5)/(9–4\/5)(9+4\/5)

=(90+40\/5–36\/5–80)/(81–80)

=10–4\/5/1

=10–4\/5

If x=9-4√5, what is x-1/x?

If x=9-4√5, then what is x^2+1/x^2?

What is x+1/x if x value is 5-2√3?

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