if x=9+4 root 5 then find the value of x+1/x
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x=9+4root5
1/x=9-4root 5 (rationalisation )
Now,
x+1/x
=9+4root5+9-4root5
=9+9
=18
1/x=9-4root 5 (rationalisation )
Now,
x+1/x
=9+4root5+9-4root5
=9+9
=18
yogeshwarbvss27:
sweta answer
a^3+b^3+c^3-3abc= (a+b+c)(a^2+b^2+c^2-ab-bc-ac) a^3+b^3+c^3-3abc =(0)(a^2+b^2+c^2-ab-bc-ac) a^3+b^3+c^3-3abc =0 a^3+b^3+c^3=3abc
a^3+b^3+c^3-3abc= (a+b+c)(a^2+b^2+c^2-ab-bc-ac) a^3+b^3+c^3-3abc =(0)(a^2+b^2+c^2-ab-bc-ac) a^3+b^3+c^3-3abc =0 a^3+b^3+c^3=3abc
tqsm
ok
hmmmmm
can i ask u another plzz
ok
if mean of 20, 14, 16, 19, p and 21 is 27 the find the value of 'p'
this sum is from statistics
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