Question

if x=-9 is a rout of x 3 7
2 x 2 = 0
7 6 x
then the other rout of are
​

Answer 1

Answer:

ANSWER

∣

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∣

∣

∣

∣

∣

x

2

7

3

x

6

7

2

x

∣

∣

∣

∣

∣

∣

∣

∣

=0

⇒x(x

2

−12)−3(2x−14)+7(12−7x)=0

⇒x

3

−67x+126=0

if x=−9

(−9)

3

−67(−9)+126=−729+729=0

∴(x+9) is the factor of x

3

−67x+126

⇒x

3

−67x+126=(x+9)(x

2

−9x+14)

⇒ other two roots a,b are 2,7

∴ab=14

Answer 2

Step-by-step explanation:

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