Question

If x =9 is one of the root of the quadratic equations X2 - 11X+K=0THEN FIND THE VALUE OF K
​

Answer 1

Answer:

when X= 9

p(X)=x2-11k+k

p(9)=9^2-11k+k

So,

9^2-11k+k=0

81-10k=0

-10k=-81

10k=81

k=81/10

k=8.1

Explanation:

please mark as brainliest

Answer 2

Answer:

Given- X=9

equation - X2-11X+K

putting the value of X in the equation, we get

X2-11X+K=9^2-11*9+K=0

82-99+K=0

-17+K=0

K=17