Question

If x=9 is one root of the quadratic equation x²-2kx-6=0 then find value ok k.​

Answer 1

Explanation:

Let

p(x) = x²-2kx-6=0

x= 9 is one root of the quadratic equation

Remainder = p(9) = 0

=> p(9)=0

=> (9)²-2k(9) - 6 = 0

=> 81-18k-6=0

=> -18k=6-81

=> - 18k = -75

=> k=75/18

=> k=25/6