Question

if x^91+91 is divided by x+1 then the remainder is

Answer 1

Hey friend, here is the answer -

Let g(x) = x^91+91

Zero of x+1 = -1

Remainder

g(x) = x^91+91

g(-1) = -1^91+91

= -91 + 91

= 0

Hence, when x^91 + 91 is divided by x+1 then the remainder is 0.

Hope it will help

Please mark my answer brainliest