if ( x^99+99) is divided by x+1 then find the remainder.
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3
let p(x)=99x-99
zero of x+1 is (-1)
so p (-1)= 99(-1)-99
= -99-99
=0
so by remainder theoram the remainder is 0 and X+1 is a factor of p (x)
Answered by
2
Answer: let p(x)=99x-99
zero of x+1 is (-1)
so p (-1)= 99(-1)-99
= -99-99
=0
so by remainder theoram the remainder is 0 and X+1 is a factor of p (x)
hope this helps you
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