If x = a^2×b^3 where a and b are prime factors of x ,then the number of factors of x is ________?
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the factors of x is 2factors
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Explanation...
number of factor of x =(a+1)(b+1)(c+1)
x=a^2(square)+b^3(cube)
therefore number of factor of x=(2+1)(3+1)=
=3 multiplied by 4 = 12.
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