Math, asked by pinkirakeshkumarsing, 10 months ago

If x = a^2×b^3 where a and b are prime factors of x ,then the number of factors of x is ________?​

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Answered by DeviSathvika
2

the factors of x is 2factors

Answered by adhyayansmart
3

Answer:

Explanation...

number of factor of x =(a+1)(b+1)(c+1)

x=a^2(square)+b^3(cube)

therefore number of factor of x=(2+1)(3+1)=

=3 multiplied by 4 = 12.

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