If x+a = 2,prove x 3 + a 3 +6ax - 8 = 0
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x3+a3+6ax-8
=(x+a)3-3ax(x+a)+6ax-8
=2³-6ax+6ax-8=0
=(x+a)3-3ax(x+a)+6ax-8
=2³-6ax+6ax-8=0
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