If x + a= 9 and xa=six
Find the value of Xsquare and A square...
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(x+a)^2=x^2+a^2+2xa
9^2=x^2+a^2+2*6
81=x^2+a^2+12
81-12=x^2+a^2
69=x^2+a^2
9^2=x^2+a^2+2*6
81=x^2+a^2+12
81-12=x^2+a^2
69=x^2+a^2
Answered by
8
Answer :
The value of x² + a² = 69
Step-by-step explanation :
x + a = 9
On squaring both sides ;
( x + a )² = ( 9 )²
⇒ x² + a² + 2 ax = 81
⇒ x² + a² + 2 * 6 = 81
⇒ x² + a² + 12 = 81
⇒ x² + a² = 81 - 12
⇒ x² + a² = 69
Hence, the value of x² + a² is 69.
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