If x=a+√(a^2-1)
then a
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Step-by-step explanation:
x = a + √a^2 +1
1/x = 1/(a + √a^2 + 1 )
Multiplying and dividing R.H.S. by
(a - √(a^2+1) ) , we get
1/x = (a - √(a^2 +1) )/(a^2 -(a^2 +1) )
=> 1/x = -(a - √(a^2 +1) ) = -a + √(a^2 +1)
Subtracting 1/x from x we get
x - 1/x = 2a
=> a = (x - 1/x )/2
Hope it helps !!!
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