Question

If x = (a/b) + (b/a), y = (b/c) + (c/b) and z = (c/a) + (a/c), then what is the value of xyz – x2 – y2 – z2?

A) – 4 B) 2 C) – 1 D) – 6

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Answer is -4

Step-by-step explanation:

Sol. GIVEN

x=a/b+b/a, y=b/c+c/b, &z=c/a+a/c

put a = b = c = 1

x = y = z will come out as 2

put in eqn. to find xyz – (x² + y² + z²)

⇒ 2 × 2 × 2 – (4 + 4 + 4)

⇒ – 4