Question

if x-a/b+c + x-b/a+c + x-c/b+a = 3, where a,b and c are three positive real numbers, then find the value of 2x-1

Answer 1

Answer:

x=a+b+c

Step-by-step explanation:

x-a/b+c-1   x-b/c+a-1  x-c/a+b-1=0

x-a-b-c/b+c  + x-b-c-a/c+a  +  x-c-a-b/a+b=0

(x-a-b-c) [1/b+c +  1/c+a +  1/a+b]=0

(x-a-b-c)k=0

x-a-b-c=0

x=a+b+c