Question

if x+a/b+c + x+b/c+a + x+c/a+b + 3 = 0 , a>0, b>0, c>0, then the value of x is:

please answer early
it's urgent​

Answer 1

Answer:

.. the fastest way I know how: Subtract [math]3[/math] from both sides but creatively: [math]\dfrac{x-a}{b+c}-1 +\dfrac{x-b}{a+c}-1+\dfrac{x-c}{a+b}-1=0\tag*{}[/math] ...