Question

if x=a(b-c) y=b(c-a) z=c(a-b) then x^2/yz+y^2/zx+z^2/xy=?

Answer 1

ANSWER ::

Clearly x + y + z =0

So we have x³ + y³ + z³ = 3xyz

Now

x^2/yz+y^2/zx+z^2/xy

= x³ + y³ + z³ / xyz

= 3xyz / xyz

= 3

Please check it

Mark it Brainlist

FOLLOW ME

THANK YOU