Question

if x=a-b,y=a+b and z=a^2+b^2 find xyz.​

Answer 1

Step-by-step explanation:

x=a-b

y=a+b

z=a^2+b^2

xyz=(a-b)(a+b)(a^2+b^2)

=(a^2-b^2)(a^2+b^2)

=(a^4-b^4)

Answer 2

Answer:

a⁴ - b⁴

Step-by-step explanation:

Given : X = a - b

Y = a + b

Z = a² + b²

=> xyz = ( a - b )( a + b )( a² + b² )

=> xyz = ( a² - b² )( a² + b² )

=> xyz = ( a² )² - ( b² )²

Therefore , xyz = a⁴ - b⁴