If x =a-b, y=b-c and z=c-a then find the value of (a+b) x+(b+c) y+(c+a) z.
please solve this problem........
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Answer:
Given x=b-c ,y=c-a and z=a-b
Then x
2
−y
2
+z
2
+2xz
=(b−c)
2
−(c−a)
2
+(a−b)
2
+2(b−c)(a−b)=b
2
−2bc+c
2
−c
2
−a
2
+2ac+a
2
+b
2
−2ab+2ab−2ac−b
2
+2bc=0
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