Question

If x =a+ bt^2, then how v = 2bt?

Answer 1

Given x= a + b*t^2

We know that v = dx/dt

which means differentiation of x with respect to t

Now by putting value of x we get,

v = d(a+b*t^2)/dt

Now since a is constant so its differentiation with respect to t will be 0

and differentiation of b*t^2 = 2bt because dx^n/dx= n*x^n-1

Therefore v= 2bt

Answer 2

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