Question

If x = a cos 0 and y = b sin 0, then b2x2 + a2y2 =
(a) ab
(b) b² + a²
(c) a²b²
(d) a4b4

Answer 1

Answer:

Your answer is (c) a2b2

Answer 2

Given,

$\[x = a\cos 0,y = b\sin 0\]$

Solution,

$\[\begin{array}{l}x = a\\y = 0\end{array}\]$

Calculate the value.

$\[\begin{array}{l} = {b^2}{x^2} + {a^2}{y^2}\\ = {b^2}{a^2} + {a^2} \times {0^2}\\ = {a^2}{b^2}\end{array}\]$

Hence the value is $\[{a^2}{b^2}\]$

The correct option is (c), i.e. $\[{a^2}{b^2}\]$