Question

If x = a cos ^2 theta + b sin ^2 theta then ( x-a)( b-x) =

Answer 1

Answer:

(b-a)².(sinØ.cosØ)²

Step-by-step explanation:

x = acos²Ø+bsin²Ø

x = a(1-sin²Ø)+bsin²Ø

x = a-asin²Ø+bsin²Ø

x-a = sin²Ø.(b-a)

Again,

x = acos²Ø+bsin²Ø

x = acos²Ø+b(1-cos²Ø)

x = acos²Ø+b-bcos²Ø

b-x = bcos²Ø-acos²Ø

b-x = cos²Ø.(b-a)

A/Q,

(x-a)(b-x) = sin²Ø.(b-a).cos²Ø.(b-a)

= (b-a)².(sinØ.cosØ)².

Answer 2

Step-by-step explanation:

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