if x = a ( cos 2t + 2t sin 2t ) and y = a ( sin 2t - 2t cos 2t ) , then find dx/dy .
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x=a(cos2t+2tsin2t)
dt
dx
=a(−2sin2t+2sin2t+4tcos2t)=4at cos2t
dt
2
d
2
x
=4acos2t−8atSin2t
y=a(sin2t−2tcos2t)
dt
dy
=a(2cos2t−2cos2t+4tsin2t)=4atsin2t
dt
2
d
2
y
=4aSin2t+8atcos2t
So
dx
2
d
2
y
=
4Cos2t−8tSin2t
4Sin2t+8tCos2t
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