If x= a cos 3 theta and y= b sin3 theta . P.T. (x/a)2/3+(y/b)2/3 = 1
Answers
Answered by
30
put the values of x and y in the equation .
(acos^3theta/a)2/3 + (bsin^3theta)2/3
a^2cos^2theta/a^2 + b^2sin^2theta/b^2
cos^theta + sin^theta
1
1=1
LHS=RHS
(acos^3theta/a)2/3 + (bsin^3theta)2/3
a^2cos^2theta/a^2 + b^2sin^2theta/b^2
cos^theta + sin^theta
1
1=1
LHS=RHS
Answered by
41
Here is the answer. Hope it helps
Attachments:
Similar questions