Question

if x=a cos alpha y= b sin alpha find the value of b²x²+a²y²​

Answer 1

Answer:

a²b²

Step-by-step explanation:

b²x²+a²y²

=> a² b²cos²A + a²b²sin²A                  [A=alpha]

=> a²b²(cos²A + sin²A)

=> a²b²            [cos²A + sin²A = 1]