If x=a cos theta and y=b sin theta, find dy/dx?
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Hey there !!!!
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x= acosθ
Differentiating wrt to θ
dx/dθ = -asinθ--Equation 1
y=bsinθ
differentiating wrt to θ
dy/dθ = bcosθ---Equation 2
Equation 2/ Equation 1
= dy/dθ/dx/dθ = bcosθ/-asinθ
=dy/dx = -bcotθ/a
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Hope this helped you.................
~~~~~~~~~~~~~~~~~~~~~~~~~
x= acosθ
Differentiating wrt to θ
dx/dθ = -asinθ--Equation 1
y=bsinθ
differentiating wrt to θ
dy/dθ = bcosθ---Equation 2
Equation 2/ Equation 1
= dy/dθ/dx/dθ = bcosθ/-asinθ
=dy/dx = -bcotθ/a
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you.................
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