Question

If x = a cos theta and y = b sin theta then b^2 x ^2 + a^2 y^2 =

Answer 1

Solution

X=a cos∅

Y=b sin∅

therefore...

b²X²+a²Y²

=b²a²cos²∅+a²b²sin²∅

=a²b²(sin²∅+cos²∅)

=a²b² (answer)

Hope this helps you ✌️

Answer 2

Answer:

1. x=a
2. y=b

• b^2a^2+a^2b^2
• 2a^2b^2
• 2(a^2b^2)