Question

if x=a cos theta and y=b sin theta then find b2x2+a2y2-a2b2

Answer 1

Answer:

$x ^{2}b^{2} + a^{2} b^{2} = a^{2} b ^{2}$

Step-by-step explanation:

x= a cos thetha

y=b sin thetha

$cos \ \alpha = (x \div a) \sin \alpha = (y \div b)$

$cos^2 \alpha + sin^2 \alpha = 1 = (x ^{2} \div a^{2} ) + (y^{2} + b^{2} )$

$x ^{2}b^{2} + a^{2} b^{2} = a^{2} b ^{2}$

If my answer is correct pls mark it brainliest :)))

Answer 2

Step-by-step explanation:

please mark as brainlist