Question

If x= a cos theta ,y=b sin theta, then b2,^x2+a2^y2-a2^b2

Answer 1

Answer:

Correct option is

B

a

2

b

2

x=acosθ;y=bsinθ

cosθ=

a

x

;sinθ=

b

y

cos

2

θ+sin

2

θ=1=

a

2

x

2

+

b

2

y

2

x

2

b

2

+a

2

y

2

=a

2

b

2

.