If x= a(cosec@ - cot@) and y = b(cot@-cosec@ ), then
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it is given that,
x=a(cosec@-cot@)
y=b(cot@-cosec@)
On option verification,
xy+ab=0
a(cosec@-cot@)×b(cot@-cosec@)+ab=0
ab(cosec@-cot@)(cot@-cosec@)+ab=0
-ab(cosec²@-cot²@)+ab=0
As we know that,
(cosec²@-cot²@)=1
-ab+ab=0
Hope it helps you......
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