If x+a is a common factor of f(x) = x² + x-6 and g(x) =x² +3x -18 then find the value of a.
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Answered by
16
let (x+a) =0
then x= -a
put x=-a in f(x)
x^{2}+x-6=(-a)2-a-6=0
a2-3a+2a-6=0
a(a-3)+2(a-3)=0
(a-3)(a+2)=0
a=3,-2
now put x=-a in g(x)
x2+3x-18=(-a)2+3(-a)-18=0
a2-3a-18=0
a2-6a+3a-18=0
a(a-6)+3(a-6)=0
(a-6)(a+3)=0
a=6,-3
Answered by
3
Answer:
same as above please follow
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