If x+a is a common factor of x2+px+q & x2+mx+n than prove that a= n-q/p-n
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Step-by-step explanation:
given two polynomials are x^2+ px +q
and the second one is x^2 +mx+n
and x+a is a factor of both means x = -a would satisfy the both equation
A/Q
[-a]^2+p[-a]+q = [-a]^2 +m[-a] + n
a^2 -ap +q = a^2 - am +n
am - ap = n -q
a [m- p] =n - q
a = n-q/ m - p
which is equal to RHS
HENCE LHS = RHS
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Hope this helps you ✌️✌️
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