if X + a is a factor of 2 X square + 2 aX + 5 x + 10 then find a
Answers
Answered by
11
Let the given Equation is f(x) = 2x^2 + 2ax + 5x + 10.
According to factor theorem, if (x + 1) is a factor of f(x), then f(-a) = 0.
f(-a) = 2(-a)^2 + 2a(-a) + 5(-a) + 10 = 0
= 2a^2 - 2a^2 - 5a + 10 = 0
= -5a + 10 = 0
= -5(a - 2) = 0
a - 2 = 0
a = 2.
Therefore the value of a = 2.
Hope this helps!
According to factor theorem, if (x + 1) is a factor of f(x), then f(-a) = 0.
f(-a) = 2(-a)^2 + 2a(-a) + 5(-a) + 10 = 0
= 2a^2 - 2a^2 - 5a + 10 = 0
= -5a + 10 = 0
= -5(a - 2) = 0
a - 2 = 0
a = 2.
Therefore the value of a = 2.
Hope this helps!
siddhartharao77:
If possible brainliest it. Thanks
Answered by
2
ANSWER IS GIVEN IN THE ATTACHMENT
Attachments:
Similar questions