if X + a is a factor of 2 X square + 2 Xa + 5 x + 10 find a
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HY MATE ❤❤♥♥❤❤♥♥❤❤♠♠❤❤♥♥x+a is a factor of 2x²+2ax+5x+10
therefore f(-a)=0;
substituting values,
2(-a)²+2(a)(-a)+5(-a)+10=0
2a²-2a²-5a+10=0
-5a+10=0
therefore a=2♠♠♠❤❤❤❤♥♥♥♠♠♠❤❤❤♥♥
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