.If x+a is a factor of 2x^2 +2ax +5x +10 , find a
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Answered by
1
Answer:
divide the factor by the polynomial and then by creating X + a by the remainder you will get the value of a
Answered by
0
Answer:
X+a is a factor of 2x²+2ax+5x+10
therefore f(-a)=0;
substituting values,
2(-a)²+2(a)(-a)+5(-a)+10=0
2a²-2a²-5a+10=0
-5a+10=0
therefore a=2
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