if (x+a) is a factor of 2x^2+2ax+5x+10,find a.
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If x+a is a factor of 2x^2+2ax+5x+10...............(1)
then+a=0
then x=-a
now we put x=-a in (1) and equal zero
2(-a)^2+2a(-a)+5(-a)+10=0
2a^2-2a^2-5a+10=0
-5a=-10
a=2
then+a=0
then x=-a
now we put x=-a in (1) and equal zero
2(-a)^2+2a(-a)+5(-a)+10=0
2a^2-2a^2-5a+10=0
-5a=-10
a=2
shivani12320:
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