Question

If (x+a) is a factor of 2x²+2ax + 5x + 10,then,what be will value of a.

Answer 1

Step-by-step explanation:

2(-a)² + 2a(-a) + 5(-a) + 10 = 0

2a² - 2a² - 5a + 10 = 0

-5a + 10 = 0

5a = 10

a = 2

Answer 2

Answer:

$\red {Value \: of \: a } \green { = 2}$

Step-by-step explanation:

$Let \: p(x) =2x^{2}+2ax+5x+10$

$If \: (x+a) \: is \: a \: factor \: of \: p(x) \:then \\remainder \: p(-a) = 0$

$\implies 2(-a)^{2} + 2a\times (-a)+5(-a )+ 10 = 0$

$\implies 2a^{2} - 2a^{2} -5a + 10 = 0$

$\implies -5a + 10 = 0$

$\implies -5a = -10$

$\implies a = \frac{-10}{-5} = 2$

Therefore.,

$\red {Value \: of \: a } \green { = 2}$

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