Question

If x-a is a factor of 3x^2-mx-na then prove that a=m+n/3

Answer 1

Answer:

Mark it as brainliest

Yes

Answer 2

Step-by-step explanation:

Given :

(x - a) is the factor of 3x²-mx-na

To prove :

a = (m+n)/3

Solution :

Given polynomial, 3x²-mx-na

Let p(x) = 3x²-mx-na

⇒ (x - a) is a factor

x - a = 0

x = a

Since it is a factor, when we substitute x = a in the polynomial, the result should be zero.

p(a) = 0

3(a)²- m(a) - na = 0

3(a²) - ma - na = 0

3a² - ma - na = 0

a(3a - m - n) = 0

3a - m - n = 0/a

3a - m - n = 0

3a = m + n

a = (m + n)/3

Hence proved!