Question

If (x-a) is a factor of 3x² – mx – nx , then a =
a) m+n
b) 1/2 ( m+n)
c) 1/3 ( m+n)
d) m – n

Answer 1

$\huge{\underline{\mathtt{\red{ƛ}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}} \bold \red♡$

Step-by-step explanation:

if (x-a) is the factor of 3x^2-mx-nx, then prove that a=m+n/3. therefore 3a^2-ma-na=0. Verified

Answer 2

Step-by-step explanation:

Step-by-step explanation:

if (x-a) is the factor of 3x^2-mx-nx, then prove that a=m+n/3. therefore 3a^2-ma-na=0. Verified