Question

If (x-a) is a factor of 3x² – mx – nx , then a =
m+n
a.1/2 ( m+n)
b.1/3 ( m+n)
c.m – n
please answer fast with an explanation its urgent

Answer 1

Answer:

1/3 (m+n)

Step-by-step explanation:

Given, x-a is a factor of 3x² - mx - nx;

If x-a is a factor of the equation, then x=a is a solution of the equation.

substituting, x=a;

3(a)² - m(a) - n(a) = 0

3a² - ma - na = 0

3a² - a(m+n) = 0

a[3a - (m+n)] = 0

1st Case:

a = 0

2nd Case:

3a - (m+n) = 0

3a = m+n

a = 1/3 (m+n)