If x-a is a factor of 4x²mx-na, prove that a=m+n/4
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Answered by
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Hope this helps you.....✌^_^
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anu9524:
Although there was not a (-) sign between 4x² and mx.... but I myself tried several times and didn’t get the correct answer. I guess the question itself is wrong. Anyways, thank you :)
hmmm....i also tried a lot n after that i put the -ve sign......to get the answer
Answered by
1
Given,
(x-a) is a factor of (4x²-mx-na).
To prove,
a = (m+n)/4
Solution,
We can easily solve this problem by following the given steps.
According to the question,
(x-a) is a factor of (4x²-mx-na).
When (x-a) is a factor then the value of x will be:
(x-a) = 0
x = a
Now, putting this values of x in (4x²-mx-na):
4(a)²-ma-na
Taking a common from all the three terms:
a (4a-m-n) = 0
(4a-m-n) = 0
4a-(m+n) = 0
Moving (m+n) from the left-hand side to the right-hand side will result in the change of the sign from minus to plus:
4a = (m+n)
a = (m+n)/4 [4 was in the multiplication on the left-hand side. So, it is in the division on the right-hand side.]
Hence, it is proved that a = (m+n)/4.
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