If (x+a) is a factor of f(x)= x^3+ax^2+2x-4, then what is the value of a?
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2
Answer:
x^3+ax^2-2x+a+4 Must be divisible by x+a
so,( x3+ax2−2x+a+4)/(x+a)
=x^2–2 is quotient and (a+4)-(-2a) is remainder
But the polynomial is divisible so the remainder should be 0
Thus , (a+4)-(-2a)=0
=>(a+4+2a)=0
=>3a+4=0
=>a=-4/3
Answered by
0
Answer:
The value of a is (-2).
Step-by-step explanation:
When you substitute the value of (x) = (-a) then, the result would be equal to zero as (-a) Is a factor of f(x).
Thanks...
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