If x+a is a factor of ma-nx-3x^2 then prove that a=m+n/3
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Answered by
4
Answer:
Step-by-step explanation:
given that x+a is a factor then using the remainder theorem we can say that
P(-a)=0
then,
ma-n(-a)-3(-a)^2=0
ma+na-3a^2=0
a(m+n-3a)=0
m+n-3a=0
m+n=3a
m+n/3=a
hence proved
Answered by
2
Answer:
this is your solution.
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