If ( x+a) is a factor of the polynomial 2x square + 2 ax + 5 x + 10, find the value of a
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Answered by
8
Hi friend!!
Given,( x+a) is a factor of the polynomial 2x ²+ 2 ax + 5 x + 10
So, -a satisfies the equation 2x²+2ax+5x+10=0
2(-a)²+2a(-a)+5(-a)+10=0
2a²-2a²-5a+10=0
5a=10
a=2
I hope this will help you;)
Given,( x+a) is a factor of the polynomial 2x ²+ 2 ax + 5 x + 10
So, -a satisfies the equation 2x²+2ax+5x+10=0
2(-a)²+2a(-a)+5(-a)+10=0
2a²-2a²-5a+10=0
5a=10
a=2
I hope this will help you;)
vickyjaiswal10p93atx:
super
Answered by
3
Since (x+a) is a factor
So, x+a=0
x=-a
Now,
Put x= - a
2x^2 + 2ax + 5x + 10 = 0
- 2a^2 - 2a^2 - 5a + 10 = 0
5a = 10
a = 2
So, x+a=0
x=-a
Now,
Put x= - a
2x^2 + 2ax + 5x + 10 = 0
- 2a^2 - 2a^2 - 5a + 10 = 0
5a = 10
a = 2
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