If (x – a) is a factor of the polynomials x2
+ px – q and x2
+ rx – t, then a = ?
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Answer:
a = q - p
a = t - r
Step-by-step explanation:
x - a = 0
x = a
Putting x = a in the given equation,
p (x) = x2 + px - q
p (a) = a2 + pa - q = 0
a2 = q - pa
a2/a = q - p
a = q - p
p(x) = x2 + rx - t
p(a) = a2 + ra -t = 0
a2 = t - ra
a2/a = t - r
a = t - r
So, we get,
a = q - p
a = t - r
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