Question

if X + a is a factor of x square + bx + q and X square + MX + n then prove that a = n-q/m-p

Answer 1

Hey mate,

Here is your answer.. :)

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(-a)² + p·(-a) + q = 0 --> a² -ap + q = 0 

(-a)² + m·(-a) + n = 0 --> a² -am + n = 0 

Since they both equal 0, you can set them equal to each other: 

a² -ap + q = a² -am + n 

-ap + q + -am + n 

am - ap = n-q 

a(m-p) = n-q 

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Be Brainly.. :)

Answer 2

Answer:

Step-by-step explanation: X square + MX