If x-a is a factor of x³-5x²a+4a²x+m, then find the value of m. PLS ANSWER IT FAST...
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Answered by
44
According to factor theorem if x-a is a factor of p(x) then p(a) = 0.
Since p(x) = x³-5x²a+4a²x+m
= p(a) = 0
=) a^3 - 5(a)^2 (a) + 4(a)^2 (a) + m = 0
=) a^3 - 5a^3 + 4a^3 + m = 0
=) m = 0.
Hope it's helpful to u.
Since p(x) = x³-5x²a+4a²x+m
= p(a) = 0
=) a^3 - 5(a)^2 (a) + 4(a)^2 (a) + m = 0
=) a^3 - 5a^3 + 4a^3 + m = 0
=) m = 0.
Hope it's helpful to u.
batradivjyot25:
I asked u to find the value of m...what did u answered...?? I can't understand...
if x-a is a factor of given polynomial then p(a) = 0
by factor theorem
put value of a at x then solve iy
u will get the answer ur own
Then the value of a will be 0
no value of a at x = 0
got it??
Thanks..
Ur wlcm
Answered by
3
Answer:
m=0
Step-by-step explanation:
x - a = 0
Put x = a
a³ - 5a³ + 4a³ + m = 0
-5a³ + 5a³ + m = 0
m = 0
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