Question

if (x-a) is a factor of (x3-ax2+2x-a-1), find the value of a​

Answer 1

Answer:

a=1

Step-by-step explanation:

g(x)=x-a=0

     =x=a

p(a)=(a)^3-a(a)^2+2(a)-a-1

     =a^3-a*a^2+2a-a+1

     =a^3-a^3+2a-a-1

     =2a-a-1=0

     =a-1=0

     =a=1

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Answer 2

Answer:

$\frac{1}{3}$

Step-by-step explanation:

Given:

p(x) = x³-ax²+2x-a-1

(x - a) is a factor of p(x)

we know that,

x - a = 0

x = 0+a = a

Substituting the value of x, we get,

a³ - a(a)² + 2(a) + a - 1 =0

a³ - a³ + 2a + a - 1=0

3a - 1=0

3a =1

a = $\frac{1}{3}$

Thus,

a = $\frac{1}{3}$

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