Question

If x=a, is a solution of the quadratic equation x(2x+5)=a the find the the possible values of a.

Answer 1

Answer:

a=0

Step-by-step explanation:

First, substitute a for x.

a(2a+5)=a

Then distribute the a to 2a and 5.

3a+5a=a

Find the sum of 3a and 5a.

8a=a

Then 8 times 0 is 0 so a=0.

Answer 2

Answer:

Step-by-step explanation:

X(2x+5) = a

2x^2+ 5x=a

Put the value of x which is a

2a^2+5a = a

2a^2+5a-a=0

2a^2+4a=0

2a(a+4)=0

a(a+2) =0/2

a(a+2)=0

When

A=0

A+2=0

A=-2

So the values of a=0,-2