If x-a is the factor of 3x^2-mx-nx then prove that a=m+n/3
Answers
Answered by
2
Answer:
Step-by-step explanation:
F(x) =3x²-mx-nx
G(x) =x-a
It is given that F(x) is divisible by G(x), thus from remainder their
F(a) =0
3a²-ma-na=0
3a²=ma+na
3a²=a(m+n)
Dividing by a on both sides
3a=m+n
a=(m+n) /3
Hence proved
Similar questions