if x + a is the factor of the polynomial x2 + px + q and x2 + mx + n find the value of a
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Answer:
a = (n-q) / (m-p)
Step-by-step explanation:
since x+a is the factor of both given polynomials
then,
(-a)²-pa+q = 0
=> a²-pa+q = 0................(1)
(-a)²-ma+n = 0
=> a²-ma+n = 0..............(2)
from (1) and (2)
a²-pa+q = a²-ma+n
=> -pa+q = -ma+n
=> (m-p)a = n-q
=> a = (n-q) / (m-p)
hope this helps you
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