If x=a secθ and y=b tanθ,then
Answers
Answered by
0
squaring on both sides
x²=a²sec²Ф , y²=b²tan²Ф
then
x²÷a²= sec²Ф -1
y²÷b²=tan²Ф -2
then
from 1 and 2
subtract
x²÷a²-y²÷b²=sec²Ф-tan²Ф
hence
x²÷a²-y²÷b²=1
x²=a²sec²Ф , y²=b²tan²Ф
then
x²÷a²= sec²Ф -1
y²÷b²=tan²Ф -2
then
from 1 and 2
subtract
x²÷a²-y²÷b²=sec²Ф-tan²Ф
hence
x²÷a²-y²÷b²=1
Similar questions